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6x^2-56x+130=0
a = 6; b = -56; c = +130;
Δ = b2-4ac
Δ = -562-4·6·130
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{16}=4$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-56)-4}{2*6}=\frac{52}{12} =4+1/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-56)+4}{2*6}=\frac{60}{12} =5 $
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